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!NEW! Descargar Discografia Asfalto Mediafire Rar







A: You can use the package discography: > library(discography) > data(Discography) > search(Discography, "The Beatles") > data(Discography) > search(Discography, "The Beatles") Discography with 273 pages Q: Weird exception message from appending an html element to a list I'm trying to append an html element into a list of cms items and have it come out as a list item. I'm doing this using a div wrapper in the cms template: {{ cms_item_list.append(item, item_id=item_id) }} However, the exception message I'm getting has me puzzled: Unsupported widget type If I understand correctly, that means that the format of the content of the div is different than that of the fields format. Is there a way to get the "list" output to appear without having to add a new field? A: You can either add a new field, or change the type of your existing field. Q: How to use a variable in the name of a pandas column? I'm working on a data frame where I want to concatenate a pandas string column to another column's name and a variable. This variable is an int (called temp). When I try the following df.loc[:, '**' + str(temp) + '**']: ['XXX', 'XXX'] It says TypeError: unsupported operand type(s) for +: 'int' and'str'. I understand that this may be because I'm trying to add an int to a string column, but I have no idea how to get around this. What I want to do is to get the name of a column with a variable as a suffix, like this: df.loc[:, '**' + str(temp) + '**']: ['XXX', 'XXX'] The problem is that it doesn't work. If I use df.loc[:, '**' + str(temp) + '**']: ['XXX', 'XXX'] or even df.loc[:, '**' + str(temp) + '**']: [' be359ba680


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